Questionsolve this using the quadratic formula, give the solutions 1.) $a^{2}-12 a=-27$ 2.) $2 x^{2}+5 x=-3$

Studdy Solution
Calculate the two possible solutions.
$$x_1 = \frac{-5 + 1}{4} = \frac{-4}{4} = -1$$ $$x_2 = \frac{-5 - 1}{4} = \frac{-6}{4} = -\frac{3}{2}$$
Solution for the first equation: $a_1 = 9$, $a_2 = 3$.
Solution for the second equation: $x_1 = -1$, $x_2 = -\frac{3}{2}$.