Math  /  Algebra

Question Find intervals where f(x)=2x22xf(x) = \sqrt{-2x^2 - 2x} is continuous. If multiple intervals, separate with \cup or comma. If not continuous, output \varnothing.

Studdy Solution
Therefore, the function f(x)=2x22xf(x)=\sqrt{-2 x^{2}-2 x} is continuous over the interval (1,0)(-1, 0).
The interval(s) over which the function is continuous is (1,0)(-1, 0).

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