Math  /  Algebra

QuestionStep 1 need to divide. However, we note that the denominator can be factored as follows. Q(x)=6x2+7x+1=(6x+1)()\begin{aligned} Q(x) & =6 x^{2}+7 x+1 \\ & =(6 x+1)(\square) \end{aligned} Submit Skip (you cannot come back)

Studdy Solution
Verify the complete factorization.
Substitute b=1 b = 1 back into the factorization:
(6x+1)(x+1)=6x2+6x+x+1=6x2+7x+1 (6x + 1)(x + 1) = 6x^2 + 6x + x + 1 = 6x^2 + 7x + 1
The factorization is verified as correct.
The complete factorization of Q(x)=6x2+7x+1 Q(x) = 6x^2 + 7x + 1 is (6x+1)(x+1) (6x + 1)(x + 1) .

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