QuestionStep 3 All the necessary values have been found to calculate the margin of error. We have $z_{\alpha / 2}=1.960, \bar{p}=0.557$ four decimal places. $$\begin{aligned} E & =z_{\alpha / 2} \sqrt{\frac{\bar{p}(1-\bar{p})}{n}} \\ & =1.960 \sqrt{\frac{0.5571(1-0.5571)}{359}} \\ & =\square \end{aligned}$$ Submit Skip_(you cannot come back) Submit Answer