Math  /  Algebra

QuestionStudent number: .23283 3
1. A parallel-plate capacitor has a capacitance of 10μ F10 \mu \mathrm{~F} and is charged with a 20 V power supply. A dielectric material of dielectric constant 2.0 is used to fill the space between the plates of the capacitor, which is still connected with a battery. What is the capacitance now of the capacitor in μF\mu \mathrm{F} and, what is the voltage now across the capacitor in VV C=v=\begin{array}{l} C= \\ v= \end{array}

E I=20C1=10I=2\begin{array}{l} I=20 \\ C_{1}=10 \\ I=2 \end{array}

Studdy Solution
The new capacitance is 20μF20 \, \mu F, and the new voltage is 20V20 \, V.

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