Math  /  Algebra

QuestionSubtract the radicals: 372y32y3 \sqrt{72 y^{3}} - \sqrt{2 y}, where all variables are positive real numbers.

Studdy Solution
We can factor out the common term 2y\sqrt{2y} from both terms.
(18y1)2y(18y -1) \sqrt{2y}So, the simplified form of the given expression 372y32y3 \sqrt{72 y^{3}}-\sqrt{2 y} is (18y1)2y(18y -1) \sqrt{2y}.

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