Math  /  Algebra

QuestionSULIT DBM10013: ENGINEERING MATHEMATICS I
QUESTION 2 SOALAN 2 CLOI (a) Calculate the complex numbers below in the form of a+bia+b i. Kira nombor kompleks di bawah dalam bentuk a+bia+b i. i. (5+i)2(27i)(5+i)-2(-2-7 i) [3 marks] [3 markah] ii. 4+3i27i\frac{4+3 i}{-2-7 i} [5 marks] [5 markah]
ClOI (b) Calculate the modulus, argument and sketch the Argand Diagram for 105i-10-5 i.
Hitung modulus, hujah dan lakarkan Rajah Argand untuk -10 - 5i5 i. [7 marks] [7 markah] (c) CLO2 i. Solve the following expression in an exponential form.
Selesaikan ungkapan berikut dalam bentuk eksponen. 45(cos270+isin270)×5(cos50+isin50)15(cos110+isin110)\frac{45\left(\cos 270^{\circ}+i \sin 270^{\circ}\right) \times 5\left(\cos 50^{\circ}+i \sin 50^{\circ}\right)}{15\left(\cos 110^{\circ}+i \sin 110^{\circ}\right)} [6 marks] [6 markah] ii. Given that Z1=4125Z_{1}=4 \angle 125^{\circ} and Z2=40(cos25+isin25)Z_{2}=40\left(\cos 25^{\circ}+i \sin 25^{\circ}\right). Solve the Z2×Z1Z_{2} \times Z_{1} in polar form. Diberi Z1=4125Z_{1}=4 \angle 125^{\circ} dan Z2=40(cos25+isin25)Z_{2}=40\left(\cos 25^{\circ}+i \sin 25^{\circ}\right). Selesaikan Z2×Z1Z_{2} \times Z_{1} dalam bentuk polar. [4 marks] [4 markah ] 4 SULIT

Studdy Solution
Solve Z2×Z1Z_2 \times Z_1 in polar form.
Given:
Z1=4125 Z_1 = 4 \angle 125^\circ
Z2=40(cos25+isin25)=4025 Z_2 = 40(\cos 25^\circ + i \sin 25^\circ) = 40 \angle 25^\circ
Multiply the magnitudes and add the angles:
Z2×Z1=4×40(125+25) Z_2 \times Z_1 = 4 \times 40 \angle (125^\circ + 25^\circ)
=160150 = 160 \angle 150^\circ
The result in polar form is:
160150 \boxed{160 \angle 150^\circ}

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