QuestionSuppose $f(x)=8^{x}$. a) What is the domain of $f^{-1}(x)$ ? Enter your answer using interval notation. 1 [] U $\infty$ $\pi$ $a^{\circ}$ $a^{b}$ $\sqrt{a}$ $\square$ $\sin$ $\square$ Previev Invalid Inpu b) What is the range of $f^{-1}(x)$ ? Enter your answer using interval notation.

Studdy Solution
Recall that the range of the inverse function $f^{-1}(x)$ is the domain of the original function $f(x)$.
Since the domain of $f(x)$ is $(-\infty, \infty)$,
the range of $f^{-1}(x)$ is $(-\infty, \infty)$.
$$\text{Range of } f^{-1}(x) = (-\infty, \infty)$$
Solution: a) The domain of $f^{-1}(x)$ is $(0, \infty)$. b) The range of $f^{-1}(x)$ is $(-\infty, \infty)$.