QuestionSuppose $\log a=-6, \log b=2, \log c=3$. Find $\log \left(\frac{a^{2}}{b^{5} c^{3}}\right)$. $$\log \left(\frac{a^{2}}{b^{5} c^{3}}\right)=$$ $\square$

Studdy Solution
Combine the results from the previous step to find the solution:
$\log \left(\frac{a^{2}}{b^{5} c^{3}}\right) = -12 - 10 - 9$ $\log \left(\frac{a^{2}}{b^{5} c^{3}}\right) = -31$
The value of $\log \left(\frac{a^{2}}{b^{5} c^{3}}\right)$ is:
$\boxed{-31}$