QuestionFind the dimensions of a rectangle with area $54 \mathrm{yd}^{2}$, where length is $3 \mathrm{yd}$ more than double the width.

Studdy Solution
Substitute $w =4.5 \, \mathrm{yd}$ into the equation.
$$Length =2 \times4.5 +3 =12 \, \mathrm{yd}$$The dimensions of the rectangle are a width of $4.5 \, \mathrm{yd}$ and a length of $12 \, \mathrm{yd}$.