QuestionDetermine if the lines $-3y=5x+2$, $10x-6y=-2$, and $y=-\frac{3}{5}x+1$ are parallel, perpendicular, or neither.

Studdy Solution
For Line2 and Line3, the slopes are $\frac{5}{3}$ and $-\frac{3}{5}$, respectively. The product of these slopes is $\frac{5}{3} \times -\frac{3}{5} = -1$, so these lines are perpendicular.
In conclusion, Line1 and Line2 are perpendicular, Line1 and Line3 are neither parallel nor perpendicular, and Line2 and Line3 are perpendicular.