Math  /  Data & Statistics

QuestionThe "Freshman 15" refers to the belief that college students gain 15 lb (or 6.8 kg ) during their freshman year. Listed in the accompanying table are weights (kg) of randomly selected male college freshmen. The weights were measured in September and later in April. Use the listed paired sample data, and assume that the samples are simple random samples and that the differences have a distribution that is approximately normal. Complete parts (a) through (c). September 57636057 \quad 63 \quad 60 70 52 65 749257\begin{array}{lll}74 & 92 & 57\end{array} April 58 65 64 68 53 82 92 59
Identify the P -value. P -value =0.0277=0.027^{7} (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P -value is less than the significance level, reject the null hypothesis. There is sufficient evidence to support the claim that for the population of freshman male college students, the weights in September are less than the weights in the following April. b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval leads to the same conclusion reached in part (a)?
The confidence interval is \square kg<μd<\mathrm{kg}<\mu_{\mathrm{d}}< \square kg. (Type integers or decimals roundeध to one decimal place as needed.)

Studdy Solution
The P-value is **0.027**.
Since the P-value is less than the significance level of 0.05 (implied by the problem), we reject the null hypothesis.
The 95% confidence interval for the mean weight change is (0.2,4.4)\mathbf{(-0.2, 4.4)} kg.
Since this interval *doesn't contain zero*, it supports the conclusion that there's a *real weight change*, and it's likely positive (meaning weight gain).

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord