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Math  /  Algebra

QuestionFind the inverse function n(c)n(c) for the cost equation c(n)=20n+15c(n)=20n+15. Which option is correct? A. n(c)=c−1520n(c)=\frac{c-15}{20} B. n(c)=c−2015n(c)=\frac{c-20}{15} C. n(c)=c−2015n(c)=\frac{c-20}{15} D. n(c)=c+1520n(c)=\frac{c+15}{20}

Studdy Solution
Comparing this with the given options, we see that the correct answer is option A n(c)=c−1520n(c) = \frac{c -15}{20}.
The inverse function of c(n)c(n) is n(c)=c−1520n(c) = \frac{c -15}{20}.

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