Math

QuestionThe gauge pressure at the bottom of a cylinder of liquid is 0.50 atm . The liquid is poured into another cylinder with twice the radius of the first cylinder.
Part A
What is the gauge pressure at the bottom of the second cylinder? Express your answer in atmospheres. AΣϕ ? P= atm \begin{array}{l} \sqrt[\square]{\square} A \Sigma \phi \\ \text { ? } \\ P= \\ \text { atm } \end{array}

Studdy Solution
Conclude that the gauge pressure at the bottom of the second cylinder is the same as the first cylinder:
P=0.50atm P = 0.50 \, \text{atm}
The gauge pressure at the bottom of the second cylinder is:
0.50atm \boxed{0.50 \, \text{atm}}

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