Math  /  Algebra

QuestionThe given line passes through the points (0,3)(0,-3) and (2,3)(2,3).
What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (1,1)(-1,-1) ? x+1=3(x+1)x+1=-3(x+1) v+1=13(x+1)v+1=-\frac{1}{3}(x+1) y+1=13(x+1)y+1=\frac{1}{3}(x+1) y+1=3(x+1)y+1=3(x+1)

Studdy Solution
Since parallel lines have the same slope, the slope of the line we are looking for is also 33.
Use the point-slope form of the equation of a line, which is:
yy1=m(xx1)y - y_1 = m(x - x_1)
Substitute the point (1,1)(-1, -1) and the slope 33:
y(1)=3(x(1))y - (-1) = 3(x - (-1))
Simplify the equation:
y+1=3(x+1)y + 1 = 3(x + 1)
The equation of the line in point-slope form is:
y+1=3(x+1) y + 1 = 3(x + 1)

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