Math  /  Algebra

QuestionThe graph shows an exponential function.
What is the equation of the function? (A) y=(23)xy=\left(\frac{2}{3}\right)^{x} (C) y=2(32)xy=2\left(\frac{3}{2}\right)^{x} (B) y=2(3)xy=2(3)^{x} (D) y=3(23)xy=3\left(\frac{2}{3}\right)^{x}

Studdy Solution
La ecuación de la función es y=23x y = 2 \cdot 3^x .
Comparamos con las opciones dadas:
(A) y=(23)x y = \left(\frac{2}{3}\right)^x
(B) y=23x y = 2 \cdot 3^x
(C) y=2(32)x y = 2 \left(\frac{3}{2}\right)^x
(D) y=3(23)x y = 3 \left(\frac{2}{3}\right)^x
La opción correcta es (B) y=23x y = 2 \cdot 3^x .
La ecuación de la función es:
y=23x \boxed{y = 2 \cdot 3^x}

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