Math / AlgebraQuestion31−1 tions -matriges ]B=[163−5−24]C=[4−612] F =[31−12032×3]⋅[163−5−24]=[8(1)+1(3)+(−1)(−2)9−424]A=[163−5−24]⋅[31−12032×3]=[15117]3×2\begin{array}{l} \left.\begin{array}{ccc} 3 & 1 & -1 \\ \text { tions -matriges } \end{array}\right] \quad B=\left[\begin{array}{cc} 1 & 6 \\ 3 & -5 \\ -2 & 4 \end{array}\right] \quad C=\left[\begin{array}{cc} 4 & -6 \\ 1 & 2 \end{array}\right] \quad \text { F } \\ =\left[\begin{array}{ccc} 3 & 1 & -1 \\ 2 & 0 & 3 \\ 2 \times 3 \end{array}\right] \cdot\left[\begin{array}{cc} 1 & 6 \\ 3 & -5 \\ -2 & 4 \end{array}\right]=\left[\begin{array}{cc} 8(1)+1(3)+(-1)(-2) & 9 \\ -4 & 24 \end{array}\right] \\ A=\left[\begin{array}{cc} 1 & 6 \\ 3 & -5 \\ -2 & 4 \end{array}\right] \cdot\left[\begin{array}{ccc} 3 & 1 & -1 \\ 2 & 0 & 3 \\ 2 \times 3 \end{array}\right]=\left[\begin{array}{ccc} 15 & 1 & 17 \\ & & \end{array}\right] \\ 3 \times 2 \end{array}3 tions -matriges 1−1]B=⎣⎡13−26−54⎦⎤C=[41−62] F =⎣⎡322×310−13⎦⎤⋅⎣⎡13−26−54⎦⎤=[8(1)+1(3)+(−1)(−2)−4924]A=⎣⎡13−26−54⎦⎤⋅⎣⎡322×310−13⎦⎤=[15117]3×2Studdy SolutionThe second row is [−1 3 −18][-1 \ 3 \ -18][−1 3 −18].The third row is [2 −2 14][2 \ -2 \ 14][2 −2 14].View Full Solution - FreeWas this helpful?
