Math  /  Calculus

QuestionCalculate the integral 02(x2+1)exdx\int_{0}^{2}\left(x^{2}+1\right) e^{-x} dx.

Studdy Solution
Evaluate the equation at the limits of0 and2.
02(x2+)exdx=e2e2+2e22+0=3e23\int_{0}^{2}\left(x^{2}+\right) e^{-x} dx = -e^{-2} - e^{-2} +2e^{-2} -2 +0 - = -3e^{-2} -3The solution to the integral 02(x2+)exdx\int_{0}^{2}\left(x^{2}+\right) e^{-x} dx is 3e23-3e^{-2} -3.

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