Math  /  Calculus

QuestionCalculate the integral from 0 to 7 of (x2+1)ex(x^{2}+1) e^{-x}.

Studdy Solution
Calculate the final result0(x2+)exdx=50e++14e+2=36e+3\int_{0}^{} (x^2 +) e^{-x} dx = -50e^{-} + +14e^{-} +2 = -36e^{-} +3So, the value of the integral is 36e+3-36e^{-} +3.

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