QuestionEvaluate the integral $\int_{0}^{\pi / 6} \frac{\sin t}{\cos ^{2} t} d t$.

Studdy Solution
implify the fractions.
$$\frac{1}{\sqrt{3}/2} - \frac{1}{1} =2\sqrt{3} -1$$So, the solution to the integral $\int_{0}^{\pi /6} \frac{\sin t}{\cos ^{2} t} d t$ is $2\sqrt{3} -1$.