Math  /  Calculus

QuestionCalculate the integral from 1 to 2 of w2lnwdww^{2} \ln w \, dw.

Studdy Solution
Further simplify the expression.
2w2lnwdw=83ln279\int_{}^{2} w^{2} \ln w d w = \frac{8}{3} \ln2 - \frac{7}{9}So, the value of the integral 2w2lnwdw\int_{}^{2} w^{2} \ln w d w is 83ln279\frac{8}{3} \ln2 - \frac{7}{9}.

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