Math / CalculusQuestionCalculate the integral: ∫t2(t3−3)3dt\int t^{2}(t^{3}-3)^{3} dt∫t2(t3−3)3dtStuddy Solutionimplify the equation.3⋅(t3−3)44+C=12(t3−3)4+C\frac{}{3} \cdot \frac{(t^{3}-3)^{4}}{4} + C = \frac{}{12} (t^{3}-3)^{4} + C3⋅4(t3−3)4+C=12(t3−3)4+CSo, the solution to the integral ∫t2(t3−3)3dt\int t^{2}\left(t^{3}-3\right)^{3} d t∫t2(t3−3)3dt is 12(t3−3)4+C\frac{}{12} (t^{3}-3)^{4} + C12(t3−3)4+C. View Full Solution - FreeWas this helpful?