Math  /  Calculus

Questionx2cosx3dx=\int x^{2} \cos x^{3} d x=

Studdy Solution
Substitute back to the original variable xx:
13sin(u)+C=13sin(x3)+C \frac{1}{3} \sin(u) + C = \frac{1}{3} \sin(x^3) + C
The solution to the integral is:
13sin(x3)+C \boxed{\frac{1}{3} \sin(x^3) + C}

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