Math  /  Geometry

QuestionThe line x+5y+22=0x+5 y+22=0 intersects the circle x2+y2+4x+8y6=0x^{2}+y^{2}+4 x+8 y-6=0 at the point AA and BB. Find the coordinates of AA and BB. Answer a. A(7,3),B(3,5)A(7,-3), B(3,5) b. A(7,3),B(3,5)A(7,-3), B(3,-5) c. A(6,3),B(3,7)A(6,-3), B(3,-7) d. A(6,3),B(3,7)A(6,-3), B(3,-7)

Studdy Solution
Verify the points (7,3)(-7, -3) and (3,5)(3, -5) by substituting them back into the circle equation.
For (7,3)(-7, -3):
(7)2+(3)2+4(7)+8(3)6=49+928246=0 (-7)^2 + (-3)^2 + 4(-7) + 8(-3) - 6 = 49 + 9 - 28 - 24 - 6 = 0
For (3,5)(3, -5):
(3)2+(5)2+4(3)+8(5)6=9+25+12406=0 (3)^2 + (-5)^2 + 4(3) + 8(-5) - 6 = 9 + 25 + 12 - 40 - 6 = 0
Both points satisfy the circle equation.
The coordinates of points AA and BB are:
A(7,3) and B(3,5) A(-7, -3) \text{ and } B(3, -5)
Therefore, the correct answer is not among the given options indicating a miscalculation or a typo in the options. The correct points should be:
A(7,3) and B(3,5) A(-7, -3) \text{ and } B(3, -5)

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