Questionuscles.
6. The magnifying power of terrestrial teles cope is 16 . when it is in normal adjustment and thelengthof the tclescope is 118 cm . If the focal length of the reccting lens is 5 cm , the focal lengths of the objective and the eye-piecer dre?

Studdy Solution
Substitute $f_e = 6.94 \text{ cm}$ back into the equation $f_o = 16 f_e$ to find $f_o$.
$$f_o = 16 \times 6.94$$ $$f_o = 111.04 \text{ cm}$$
The focal lengths of the objective and the eyepiece lenses are $f_o = 111.04 \text{ cm}$ and $f_e = 6.94 \text{ cm}$, respectively.