Math  /  Algebra

QuestionThe price pp (in dollars) and the quantity xx sold of a certain product satisfy the demand equation x=6p+300x=-6 p+300. Answer parts (a) through ( g ). (a) Find a model that expresses the revenue R as a function of p . (Remember, R=xp\mathrm{R}=\mathrm{xp}.) R(p)=6p2+300pR(p)=-6 p^{2}+300 p (Simplify your answer. Use integers or decimals for any numbers in the expression.) (b) What is the domain of R ? Assume that R is nonnegative. A. The domain is {p\{p \mid \square p\leq \mathrm{p} \leq \square (Simplify your answers. Type integers or decimals.) B. The domain is the set of all real numbers.

Studdy Solution
(a) The revenue function is R(p)=6p2+300pR(p) = -6p^2 + 300p. (b) The domain of RR is {p0p50}\{p \mid 0 \leq p \leq 50 \}.

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