Math  /  Algebra

QuestionDetermine the number of students in a classical music lecture class who like different composers using a Venn diagram. Let M = Mozart, B = Beethoven, H = Haydn. Find the number of students who like: (a) exactly 2 composers, (b) exactly 1 composer, (c) none of the composers, (d) M but not B or H.

Studdy Solution
To find the number of students who like Mozart but neither Beethoven nor Haydn, use the number of students who like exactly one composer from Mozart's set.
Monly=Number of students who like Mozart but neither Beethoven nor Haydn |M|_{\text{only}} = \text{Number of students who like Mozart but neither Beethoven nor Haydn}
Now let's perform the calculations:
STEP_2: Monly=381521+9=11 |M|_{\text{only}} = 38 - 15 - 21 + 9 = 11
STEP_3: Bonly=381516+9=16 |B|_{\text{only}} = 38 - 15 - 16 + 9 = 16
STEP_4: Honly=332116+9=5 |H|_{\text{only}} = 33 - 21 - 16 + 9 = 5
STEP_6: MBonly=159=6 |MB|_{\text{only}} = 15 - 9 = 6
STEP_7: MHonly=219=12 |MH|_{\text{only}} = 21 - 9 = 12
STEP_8: BHonly=169=7 |BH|_{\text{only}} = 16 - 9 = 7
STEP_11: None=68(11+16+5+6+12+7+9)=6866=2 \text{None} = 68 - (11 + 16 + 5 + 6 + 12 + 7 + 9) = 68 - 66 = 2
The answers to the questions are: (a) The number of students who like exactly two composers is MBonly+MHonly+BHonly=6+12+7=25|MB|_{\text{only}} + |MH|_{\text{only}} + |BH|_{\text{only}} = 6 + 12 + 7 = 25. (b) The number of students who like exactly one composer is Monly+Bonly+Honly=11+16+5=32|M|_{\text{only}} + |B|_{\text{only}} + |H|_{\text{only}} = 11 + 16 + 5 = 32. (c) The number of students who like none of the composers is 22. (d) The number of students who like Mozart, but neither Beethoven nor Haydn is Monly=11|M|_{\text{only}} = 11.

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