Math  /  Algebra

QuestionFor the function P(x)=0.74x2+22x+75P(x)=-0.74 x^{2}+22 x+75, what constraints ensure profits are at least \175,000?Options:175,000? Options: -3.09 \leq x \leq 5.6or or 0 \leq x < 5.6$?

Studdy Solution
The solutions to the inequality 0.74x+22x1000-0.74 x^{}+22 x -100 \geq0 are the intervals (,x][x,)(-\infty, x_{}] \cup [x_{}, \infty), where xx_{} and xx_{} are the roots of the quadratic equation. However, since xx represents the number of calculators produced, it cannot be negative. Therefore, the reasonable constraints for the model are 0x5.60 \leq x \leq5.6 and 24.13x24.13 \leq x.
The correct answer is 0x5.60 \leq x \leq5.6 and 24.13x24.13 \leq x.

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