Math  /  Word Problems

QuestionCalculate the joules needed to heat 32.1 g of aluminum from 21.0C21.0^{\circ} \mathrm{C} to 29.5C29.5^{\circ} \mathrm{C} using 0.897 J/gC0.897 \mathrm{~J} / \mathrm{g}^{\circ} \mathrm{C}.

Studdy Solution
Calculate the heat.
q=32.1 g×0.897 J/gC×.5C=244.3 Jq =32.1 \mathrm{~g} \times0.897 \mathrm{~J} / \mathrm{g}^{\circ} \mathrm{C} \times.5^{\circ} \mathrm{C} =244.3 \mathrm{~J}The amount of heat required to heat32.1 grams of aluminum from 21.0C21.0^{\circ} \mathrm{C} to 29.5C29.5^{\circ} \mathrm{C} is244.3 Joules.

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