Math  /  Calculus

QuestionFind the distance from the origin when the particle stops, given v=9t3t2v=9t-3t^{2} m/s and starts at t=0t=0.

Studdy Solution
Calculate the distance.
Distance=[92(9)27]0=40.527=13.5mDistance = \left[ \frac{9}{2}(9) -27 \right] -0 =40.5 -27 =13.5 \, mThe distance of the particle from the origin when the particle comes to instantaneous rest is13.5 meters.

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