Math  /  Geometry

QuestionA spiral is made of semicircles with the first diameter 10 cm10 \mathrm{~cm}, each next being 45\frac{4}{5} of the last.
1) Find the total length of the spiral.
2) How far is point EE (midpoint of the 6th semicircle) from point AA?

Studdy Solution
Calculate the distance from AA to $$.
AE=(45)645=×(45)65=50×((45)6)cmAE = \frac{ - (\frac{4}{5})^6}{ - \frac{4}{5}} = \times \frac{ - (\frac{4}{5})^6}{\frac{}{5}} =50 \times ( - (\frac{4}{5})^6) \, cmSo, the total length of the spiral is 25πcm25\pi \, cm and the distance from AA to $$ is $50 \times ( - (\frac{4}{5})^6) \, cm$.

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