Question$\begin{array}{l}x-5 y=15 \\ -x+3 y=-11\end{array}$

Studdy Solution
Verify the solution by substituting $x = 5$ and $y = -2$ back into the original equations:
For the first equation:
$5 - 5(-2) = 15 \quad \Rightarrow \quad 5 + 10 = 15 \quad \Rightarrow \quad 15 = 15 \quad \text{True}$
For the second equation:
$-5 + 3(-2) = -11 \quad \Rightarrow \quad -5 - 6 = -11 \quad \Rightarrow \quad -11 = -11 \quad \text{True}$
Both equations are satisfied.
The solution to the system is $x = 5$ and $y = -2$.