Math  /  Trigonometry

QuestionThe terminal side of angle AA in standard position goes through the point P(5,2)P(-5,-2). Draw the ref triangle in the cartesian plane that is made by the point, by first plotting the point and then clickin all of the vertices of the triangle. If a trigonomic value is undefined then answer INF.
Clear All Draw: Polygon
Find the following: (round to 3 decimal places) sinA=cosA=tanA=A=\begin{array}{l} \sin A=\square \\ \cos A=\square \\ \tan A=\square \\ A=\square \end{array}
The reference angle = \square

Studdy Solution
Find the angle A A using the inverse tangent function: A=tan1(0.4)21.801 A = \tan^{-1}(0.4) \approx 21.801^\circ
Since the point P(5,2) P(-5, -2) is in the third quadrant, the actual angle A A is: A=180+21.801=201.801 A = 180^\circ + 21.801^\circ = 201.801^\circ
The reference angle is the acute angle formed with the x-axis, which is: Reference angle=180201.801=21.801 \text{Reference angle} = 180^\circ - 201.801^\circ = 21.801^\circ
The trigonometric values and angles are:
sinA=0.371cosA=0.928tanA=0.4A=201.801Reference angle=21.801\begin{array}{l} \sin A = -0.371 \\ \cos A = -0.928 \\ \tan A = 0.4 \\ A = 201.801^\circ \\ \text{Reference angle} = 21.801^\circ \end{array}

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