Math  /  Trigonometry

QuestionThe unit circle is shown below. Complete the following. (a) Sketch θ=30\theta=-30^{\circ} in standard position on the unit circle.
Find the lengths of the legs of its reference triangle. These are labeled aa and bb in the figure below, when an angle is sketched. Then use your reference triangle to find the coordinates of point PP. Use exact values and not decimal approximations. a=b=P=(,)\begin{array}{l} a=\square \\ b=\square \\ P=(\square, \square) \end{array}

Studdy Solution
The coordinates of point PP are given by (a,b)(a, b), which are the x and y coordinates of the point on the unit circle.
Therefore, P=(32,12)P = \left(\frac{\sqrt{3}}{2}, -\frac{1}{2}\right).
The lengths of the legs and the coordinates of point PP are:
a=32b=12P=(32,12)\begin{array}{l} a = \frac{\sqrt{3}}{2} \\ b = -\frac{1}{2} \\ P = \left(\frac{\sqrt{3}}{2}, -\frac{1}{2}\right) \end{array}

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