Math  /  Algebra

QuestionFind the wind chill WW for t=5Ct=5^{\circ} C and v=19 m/sv=19 \mathrm{~m/s}. Use the formula provided. WCW \approx \square^{\circ} C

Studdy Solution
Round the wind chill factor to the nearest degree.
W11CW \approx -11^{\circ}CThe wind chill for an air temperature of 5C5^{\circ}C and a wind speed of 19m/s19m/s is approximately 11C-11^{\circ}C.

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