Math  /  Probability

Question In a group of two people, the probability of not having the same birthday is 365365364365\frac{365}{365} \cdot \frac{364}{365}. Explain why this is so, ignoring leap years and assuming 365 days in a year. The first person can have any of the \square days, and the second person must have one of the remaining \square days to not have the same birthday.

Studdy Solution
The final probability that two people selected at random do not have the same birthday is 364365\frac{364}{365}.
The first person can have a birthday on 365 of the 365 days. In order for the second person to not have the same birthday, they must have one of the remaining 364 birthdays.

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