Math  /  Data & Statistics

QuestionThis test: 25 point(s) possible This question: 3 point(s) possible Submit test
A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal Complete parts (a) and (b) below. Use a 005 significance level for both parts \begin{tabular}{|c|c|c|} \hline & \multicolumn{2}{|c|}{ Proctored } \\ \hlineμ\mu & Nonproctored \\ \hlineμ\mu & μ1\mu_{1} & μ2\mu_{2} \\ \hlinenn & 35 & 33 \\ \hlinexx & 76.44 & 83.08 \\ \hliness & 11.74 & 21.48 \\ \hline \end{tabular} D. Keject H0\mathrm{H}_{0}. Ihere is sufticient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests b. Construct a confidence interval suitable for testing the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. \square \square <μ1μ2<<\mu_{1}-\mu_{2}< (Round to two decimal places as needed.)

Studdy Solution
Our test statistic (**1.57**) is *less than* the critical value (**1.68**), so we *don't* have enough evidence to reject the null hypothesis.
Our 95% confidence interval for the difference in means (μ2μ1\mu_2 - \mu_1) is (1.67,14.95)(-1.67, 14.95).

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