Math  /  Geometry

Question To meet the required cylinder area of 11in211 \mathrm{in}^{2} within 0.01in20.01 \mathrm{in}^{2}, the cylinder diameter xx must be held in the interval [3.730,3.754][3.730, 3.754] inches.

Studdy Solution
Round the left endpoint up and the right endpoint down to the nearest thousandth as needed.
x[3.733,3.751]x \approx [3.733, 3.751]
Therefore, the diameter x x must be held within the interval [3.733,3.751] [3.733, 3.751] inches to meet the requirements for the area.

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