Math  /  Algebra

QuestionTony wants to buy a new collar for each of his 5 cats. The collars come in a choice of 6 different colors. Step 1 of 2: How many selections of collars for the 5 cats are possible if repetitions of colors are allowed?

Studdy Solution
Simplify the factorial calculation:
(105)=10×9×8×7×65×4×3×2×1=252 \binom{10}{5} = \frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1} = 252
The total number of possible selections of collars for the 5 cats is 252.

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