Math  /  Geometry

QuestionDEF\triangle \mathrm{DEF} is shown in the sketch below. G is a point on DF and EG is drawn. DG=DE=x.FG=3x2\mathrm{DG}=\mathrm{DE}=x . \quad \mathrm{FG}=\frac{3 x}{2} and EG=3x\mathrm{EG}=\sqrt{3} x. 2.1 Calculate the size of D˙\dot{D}. (4) 2.2 Calculate the area of GEF\triangle G E F in terms of xx, in its simplest form. (5)

Studdy Solution
Thus, the area of GEF\triangle GEF in terms of xx is: Area=33x24 \text{Area} = \frac{3 \sqrt{3} x^2}{4}
Solution:
1. The size of D\angle D is 120120^\circ.
2. The area of GEF\triangle GEF in terms of xx is 33x24\frac{3 \sqrt{3} x^2}{4}.

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