Math  /  Calculus

QuestionTwo engines start at the origin and meet at t=e1t=e-1. Thomas' equation is x=300ln(t+1)x=300 \ln(t+1) and Henry's is x=ktx=kt.
a. Sketch the graphs. b. Show k=300e1k=\frac{300}{e-1}. c. Find the max distance between them in the first e1e-1 minutes and when it occurs.

Studdy Solution
This gives the maximum distance between Henry and Thomas during the first ee- minutes, and the time when it occurs is t=e2t = e -2.

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