Math  /  Algebra

QuestionLösen Sie die folgenden linearen Gleichungen über R:
1. a) 3x+5=233x + 5 = 23 b) 8x12=288x - 12 = 28 c) 10y+23=310y + 23 = 3 d) 115z=2611 - 5z = 26 e) 4z9=24z - 9 = -2 f) 12y+15=1912y + 15 = 19 g) 8012t=3880 - 12t = 38 h) 16=7z+3016 = 7z + 30
2. a) 7x+3=5x+127x + 3 = 5x + 12 b) 6z+8=11z76z + 8 = 11z - 7 c) 9y+4=3y109y + 4 = 3y - 10 d) 1007x=13x100 - 7x = 13x e) 0.9x+5=1.2x3.40.9x + 5 = 1.2x - 3.4 f) 4.2t7=113.3t4.2t - 7 = 11 - 3.3t g) 0.7y+2.8=0.55y1.70.7y + 2.8 = 0.55y - 1.7 h) 0.51.7z=0.74+2.3z0.5 - 1.7z = 0.74 + 2.3z
3. a) 2x3+2=10\frac{2x}{3} + 2 = 10 b) 3x55=7\frac{3x}{5} - 5 = 7 c) x2+x3=25\frac{x}{2} + \frac{x}{3} = 25 d) y3+y4+15=y\frac{y}{3} + \frac{y}{4} + 15 = y e) z3z5=1\frac{z}{3} - \frac{z}{5} = 1 f) u5+2=u34\frac{u}{5} + 2 = \frac{u}{3} - 4 g) 3z4=2z35\frac{3z}{4} = \frac{2z}{3} - 5 h) 5y8=2y5+3\frac{5y}{8} = \frac{2y}{5} + 3
4. a) 3(x+7)=4(2x1)3(x + 7) = 4(2x - 1) b) 4(5x3)+6=104(5x - 3) + 6 = 10 c) 8(y+10)30=5y8(y + 10) - 30 = 5y d) 9(y5)=4y109(y - 5) = 4y - 10 e) 3(6v+4)=9(2v3)3(6v + 4) = 9(2v - 3) f) 8(3+2z)3z=5z88(3 + 2z) - 3z = 5z - 8 g) 5(y0.2)=1.6(3y+0.5)5(y - 0.2) = 1.6(3y + 0.5) h) 4(9w11)12(3w4)=44(9w - 11) - 12(3w - 4) = 4
5. a) 3y+52=2y3\frac{3y + 5}{2} = \frac{2y}{3} b) x+53=3x4\frac{x + 5}{3} = \frac{3x}{4} c) 2x52=4x95\frac{2x - 5}{2} = \frac{4x - 9}{5} d) 4x+306=9x4\frac{4x + 30}{6} = \frac{9 - x}{4} e) 2z+75=93z6\frac{2z + 7}{5} = \frac{9 - 3z}{6} f) 3y+44=4y65\frac{3y + 4}{4} = \frac{4y - 6}{5} g) 4z+16=z32+23\frac{4z + 1}{6} = \frac{z - 3}{2} + \frac{2}{3} h) y+23+y115=2y+35\frac{y + 2}{3} + \frac{y - 1}{15} = \frac{2y + 3}{5}

Studdy Solution
Calculate the value of x.
x=x =For the first equation, x=x =.
Note The above steps are for the first equation only. Similar steps can be followed for the rest of the equations.

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