Math  /  Calculus

QuestionUse a Maclaurin series in this table to obtain the Maclaurin series for the given function. f(x)=x2ln(1+x3)n=1()\begin{array}{r} f(x)=x^{2} \ln \left(1+x^{3}\right) \\ \sum_{n=1}^{\infty}(\square) \end{array}

Studdy Solution
The Maclaurin series for f(x)=x2ln(1+x3)f(x) = x^2 \ln(1 + x^3) is: n=1(1)n1nx3n+2\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n} x^{3n+2}

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