QuestionFind the slope of the tangent line to the curve $4xy^{3}+3xy=7$ at the point $(1,1)$ using implicit differentiation.

Studdy Solution
Calculate the value of $y'$.
$$y' = \frac{-7}{15}$$The slope of the tangent line to the curve $4 \cdot x \cdot y^{3}+3 \cdot x \cdot y=7$ at the point $(1,1)$ is $-\frac{7}{15}$.