Math  /  Calculus

QuestionUse integration tables to evaluate the integral 0π227xcosxdx\int_{0}^{\frac{\pi}{2}} 27 x \cos x d x.

Studdy Solution
Subtract the value at the lower limit from the value at the upper limit: 27(π21) 27 \left( \frac{\pi}{2} - 1 \right) =27π2271 = 27 \cdot \frac{\pi}{2} - 27 \cdot 1 =27π227 = \frac{27\pi}{2} - 27
Solution: The evaluated integral is: 0π227xcosxdx=27π227 \int_{0}^{\frac{\pi}{2}} 27 x \cos x \, dx = \frac{27\pi}{2} - 27

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