Math  /  Calculus

QuestionUse logarithmic differentiation to differentiate each function with respect to xx. You do not need to simplify or substitute for yy. y=(x2+4)3(2x41)5(4x9+5)6y=\frac{\left(x^{2}+4\right)^{3}}{\left(2 x^{4}-1\right)^{5} \cdot\left(4 x^{9}+5\right)^{6}} A) dydx=y(6xx2+4160x32x41864x84x9+5)\frac{d y}{d x}=y\left(\frac{6 x}{x^{2}+4}-\frac{160 x^{3}}{2 x^{4}-1}-\frac{864 x^{8}}{4 x^{9}+5}\right) B) dydx=y(18xx2+480x32x41+432x84x9+5)\frac{d y}{d x}=y\left(\frac{18 x}{x^{2}+4}-\frac{80 x^{3}}{2 x^{4}-1}+\frac{432 x^{8}}{4 x^{9}+5}\right) C) dydx=y(6xx2+440x32x41+864x84x9+5)\frac{d y}{d x}=y\left(\frac{6 x}{x^{2}+4}-\frac{40 x^{3}}{2 x^{4}-1}+\frac{864 x^{8}}{4 x^{9}+5}\right) D) dydx=y(6xx2+440x32x41216x84x9+5)\frac{d y}{d x}=y\left(\frac{6 x}{x^{2}+4}-\frac{40 x^{3}}{2 x^{4}-1}-\frac{216 x^{8}}{4 x^{9}+5}\right)

Studdy Solution
The derivative is dydx=y(6xx2+440x32x41216x84x9+5)\frac{dy}{dx} = y\left(\frac{6x}{x^{2}+4} - \frac{40x^{3}}{2 x^{4}-1} - \frac{216x^{8}}{4 x^{9}+5}\right), which matches option D!

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