QuestionUse the alternative method for evaluating third-order determinants (finding products along diagonals) to evaluate the determinant. $$\begin{array}{l} \left|\begin{array}{lll} 1 & 5 & 6 \\ 1 & 4 & 5 \\ 1 & 6 & 7 \end{array}\right| \\ \left|\begin{array}{lll} 1 & 5 & 6 \\ 1 & 4 & 5 \\ 1 & 6 & 7 \end{array}\right|=\square \end{array}$$