Math / AlgebraQuestionEvaluate (f∘g)(6)(f \circ g)(6)(f∘g)(6) and (g∘f)(−3)(g \circ f)(-3)(g∘f)(−3) for f(x)=x+28f(x)=\sqrt{x+28}f(x)=x+28 and g(x)=x2g(x)=x^{2}g(x)=x2.Studdy SolutionCalculate the value of g(5)g(5)g(5).g(5)=52=25g(5) =5^{2} =25g(5)=52=25So, (g∘f)(−3)=25(g \circ f)(-3) =25(g∘f)(−3)=25. View Full Solution - FreeWas this helpful?
