Math  /  Calculus

Question3. [-/2 Points]
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MARSVECTORCALC6 3.4.012. PRACTICE ANOTHER
Use the method of Lagrange multipliers to find the absolute maximum and minimum values of f(x,y)=x2+y2xy+5f(x, y)=x^{2}+y^{2}-x-y+5 on the unit disc, namely, D={(x,y)x2+y21}D=\left\{(x, y) \mid x^{2}+y^{2} \leq 1\right\}. maximum \square \square minimum
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Studdy Solution
Compare the values to determine the absolute maximum and minimum:
- The maximum value is 6+2 6 + \sqrt{2} . - The minimum value is 5 5 .
The absolute maximum value is 6+2 \boxed{6 + \sqrt{2}} and the absolute minimum value is 5 \boxed{5} .

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