Math  /  Trigonometry

QuestionUse the product-to-sum formulas to rewrite the product as a sum or difference. 8cos2θcos4θ8 \cos 2 \theta \cos 4 \theta \square

Studdy Solution
The final expression is already simplified:
=4cos(6θ)+4cos(2θ)= 4 \cos(6\theta) + 4 \cos(2\theta)
Thus, the product 8cos2θcos4θ8 \cos 2\theta \cos 4\theta is rewritten as the sum:
4cos(6θ)+4cos(2θ)\boxed{4 \cos(6\theta) + 4 \cos(2\theta)}

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